x^4+x^2y^2+25y^4=0

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Solution for x^4+x^2y^2+25y^4=0 equation:


Simplifying
x4 + x2y2 + 25y4 = 0

Reorder the terms:
x2y2 + x4 + 25y4 = 0

Solving
x2y2 + x4 + 25y4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-25y4' to each side of the equation.
x2y2 + x4 + 25y4 + -25y4 = 0 + -25y4

Combine like terms: 25y4 + -25y4 = 0
x2y2 + x4 + 0 = 0 + -25y4
x2y2 + x4 = 0 + -25y4
Remove the zero:
x2y2 + x4 = -25y4

The x term is x2y2.  Take half its coefficient (0.5y2).
Square it (0.25y4) and add it to both sides.

Add '0.25y4' to each side of the equation.
x2y2 + x4 + 0.25y4 = -25y4 + 0.25y4

Combine like terms: -25y4 + 0.25y4 = -24.75y4
x2y2 + x4 + 0.25y4 = -24.75y4

Factor a perfect square on the left side:
(x2 + 0.5y2)(x2 + 0.5y2) = -24.75y4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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